1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
|
#!/usr/bin/env python3
import RPi.GPIO as GPIO
import Keypad #import module Keypad
ROWS = 4 # number of rows of the Keypad
COLS = 4 #number of columns of the Keypad
keys = [ '1','2','3','A', #key code
'4','5','6','B',
'7','8','9','C',
'*','0','#','D' ]
rowsPins = [12,16,18,22] #connect to the row pinouts of the keypad
colsPins = [19,15,13,11] #connect to the column pinouts of the keypad
def loop():
keypad = Keypad.Keypad(keys,rowsPins,colsPins,ROWS,COLS) #creat Keypad object
keypad.setDebounceTime(50) #set the debounce time
while(True):
key = keypad.getKey() #obtain the state of keys
if(key != keypad.NULL): #if there is key pressed, print its key code.
print ("You Pressed Key : %c "%(key))
if __name__ == '__main__': #Program start from here
print ("Program is starting ... ")
try:
loop()
except KeyboardInterrupt: #When 'Ctrl+C' is pressed, exit the program.
GPIO.cleanup()
|
